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5x^2-30x=16x-48
We move all terms to the left:
5x^2-30x-(16x-48)=0
We get rid of parentheses
5x^2-30x-16x+48=0
We add all the numbers together, and all the variables
5x^2-46x+48=0
a = 5; b = -46; c = +48;
Δ = b2-4ac
Δ = -462-4·5·48
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1156}=34$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-46)-34}{2*5}=\frac{12}{10} =1+1/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-46)+34}{2*5}=\frac{80}{10} =8 $
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